cronjob to run a command at first friday of each month

hi there
i use 3 13 1-7 * 5 in cron jobs to run my command at first friday of each month,
but i see that the command run on days 1 - 7 and also all fri day!
then i found below note in wikipedia:

if both "day of month" and "day of week" are restricted (not "*"), then either the "day of month" field (3) or the "day of week" field (5) must match the current day.

so, how i can solve the problem?

crontab linux

asked 04 Oct '12, 11:03

www_9px_ir
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One Answer:

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The crontab(5) man page gives the answer in the example at the end.

3 13 1-7 * * test $(date +%u) -eq 5 && your_command

This will run on the first 7 days of the month, but will only proceed to the command if the date says its a Friday.

link

answered 21 Oct '12, 14:01

akc42
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accept rate: 0%

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Asked: 04 Oct '12, 11:03

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Last updated: 21 Oct '12, 14:01

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cronjob to run a command at first friday of each month

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